Problem 43
Easy Matrix Methods

Solve the system of differential equations: dot x_1=x_2+x_3…

Solve the system of differential equations: $$ \dot x_1=x_2+x_3,\qquad \dot x_2=x_1+x_3,\qquad \dot x_3=x_1+x_2 $$

Explanation of Method

The coefficient matrix is symmetric with the same cyclic structure seen in earlier problems in this set; the repeated eigenvalue here has full geometric multiplicity, so two independent eigenvectors suffice without any generalised eigenvectors.

  1. Write the matrix $A$ and find the characteristic polynomial using row operations.
  2. Find the eigenvector for the simple eigenvalue.
  3. Find two independent eigenvectors for the repeated eigenvalue.
  4. Assemble the general solution.

Step 1 · Characteristic equation

With $A=\begin{pmatrix}0&1&1\\1&0&1\\1&1&0\end{pmatrix}$, adding all rows to the first and factoring gives

$$ (2-\lambda)(\lambda+1)^2=0, $$

so $\lambda_1=2$ (simple) and $\lambda_{2,3}=-1$ (double).

Step 2 · Eigenvector for $\lambda_1=2$

$$ \mathbf v_1=\begin{pmatrix}1\\1\\1\end{pmatrix}. $$

Step 3 · Eigenspace for $\lambda_{2,3}=-1$

Here $A+I$ has rank 1, so the eigenspace is genuinely two-dimensional (geometric multiplicity = algebraic multiplicity, no generalised eigenvectors needed). Choose

$$ \mathbf v_2=\begin{pmatrix}1\\-1\\0\end{pmatrix},\qquad \mathbf v_3=\begin{pmatrix}1\\0\\-1\end{pmatrix}. $$

Step 4 · Verification

Differentiating the general solution and substituting confirms all three original equations hold identically. ✓


Summary Table

Quantity Value
Eigenvalues$\lambda_1=2$ (simple), $\lambda_{2,3}=-1$ (double, full geometric multiplicity)
Eigenvector for $\lambda_1$$(1,1,1)$
Eigenspace for $\lambda_{2,3}$$\{v: v_1+v_2+v_3=0\}$

Additional Notes

Result

The general solution of the system is:

$$ \begin{aligned} x_1(t) &= C_1 e^{2t} + (C_2+C_3)e^{-t},\\ x_2(t) &= C_1 e^{2t} - C_2 e^{-t},\\ x_3(t) &= C_1 e^{2t} - C_3 e^{-t}. \end{aligned} $$