Problem 23
Medium Elimination Methods

Solve by finding first integrals the symmetric four-variable…

Solve by finding first integrals the symmetric four-variable system: $$ \frac{dx}{y-u} = \frac{dy}{z-x} = \frac{dz}{u-y} = \frac{du}{x-z} $$

Explanation of Method

Pairing opposite equations shows $x+z$ and $y+u$ are each conserved; the sum of squares is conserved as well (a hidden rotational symmetry), and substituting the two linear integrals collapses the system to a simple harmonic oscillator.

  1. Add the first and third equations, and the second and fourth, to find two conserved sums.
  2. Multiply each equation by its own variable and add to find a conserved sum of squares.
  3. Substitute $z=C_1-x$, $u=C_2-y$ to reduce to a two-variable system.
  4. Differentiate once more to get a harmonic-oscillator ODE and solve it.

Step 1 · Two linear first integrals

With $\dot x=y-u$, $\dot z=u-y$, adding gives $\dot x+\dot z=0$; similarly $\dot y+\dot u=0$. Hence

$$ x+z=C_1,\qquad y+u=C_2. $$

Step 2 · Conserved sum of squares

Multiplying each equation by its variable and adding, $x\dot x+y\dot y+z\dot z+u\dot u=0$ identically, so

$$ x^2+y^2+z^2+u^2=C_3. $$

Step 3 · Reduce to two variables

Substituting $z=C_1-x$, $u=C_2-y$ gives $\dot x=2y-C_2$, $\dot y=C_1-2x$. Differentiating the first and substituting the second yields

$$ \ddot x+4x=2C_1. $$

Step 4 · Solve the oscillator

This is a harmonic oscillator with constant forcing, giving $x=\tfrac{C_1}{2}+A\cos2\tau+B\sin2\tau$, and correspondingly for $y,z,u$.

Step 5 · Verification

Substituting the explicit forms back into all four original equations, and into $\Phi_3=x^2+y^2+z^2+u^2$, confirms every relation holds identically. ✓


Summary Table

Quantity Value
Linear integrals$x+z=C_1,\ y+u=C_2$
Spherical integral$x^2+y^2+z^2+u^2=C_3$
Reduced ODE$\ddot x+4x=2C_1$ (harmonic, frequency 2)

Additional Notes

Result

The general solution of the system is:

$$ \begin{aligned} x(\tau) &= \frac{C_1}{2} + A\cos 2\tau + B\sin 2\tau,\\ y(\tau) &= \frac{C_2}{2} - A\sin 2\tau + B\cos 2\tau,\\ z(\tau) &= \frac{C_1}{2} - A\cos 2\tau - B\sin 2\tau,\\ u(\tau) &= \frac{C_2}{2} + A\sin 2\tau - B\cos 2\tau. \end{aligned} $$