Problem 197
Easy Translational Dynamics

What is the highest speed at which a car can drive around a…

What is the highest speed at which a car can drive around a horizontal circular path of radius $R = 30\ \mathrm{m}$ without skidding, if the coefficient of friction between the tyres and the road is $\mu = 0.25$?

Explanation of Method

Highest speed on a flat curve.

Step 1: Friction supplies the centripetal force

\[ \frac{mv^2}{R} \le \mu mg, \]

\[ v \le \sqrt{\mu g R} = \sqrt{0.25 \cdot 9.81 \cdot 30} = \sqrt{73.6}. \]

\[v_{\max} \approx 8.58\ \mathrm{m/s} \approx 30.9\ \mathrm{km/h}\]

$f = \frac{mv^2}{R}$ $v$ $R = 30\ \mathrm{m}$ $f \le \mu mg$ $v_{\max} = \sqrt{\mu g R} \approx 8.6\ \mathrm{m/s}$
Top view. On a flat road only the sideways friction of the tyres can turn the car, so it must supply the whole centripetal force.

Result

\[\boxed{\,v_{\max} \approx 8.58\ \mathrm{m/s} \approx 30.9\ \mathrm{km/h}\,}\]

Remark

Check. The original result is correct. $\mu = 0.25$ corresponds to a slippery (wet or icy) road; on dry asphalt ($\mu \approx 0.7$) the same curve could be taken at about 52 km/h.