Problem 28
Hard Algebraic Integrands

Evaluate the integral: I = integral dx/((5x - 2)^(5/2))

Evaluate the integral: $$ I = \int \frac{dx}{(5x - 2)^{5/2}}. $$

Explanation of Method

The integrand $(5x-2)^{-5/2}$ is again a power of a linear expression, this time with a negative fractional exponent. The linear substitution $u=5x-2$ converts it to a routine power-rule integral in $u$, after which the result is written back in terms of $x$.

  1. Substitute $u$ for the linear expression.
  2. Convert $dx$ into $du$ using the constant derivative.
  3. Integrate the resulting negative power using the power rule.
  4. Substitute back and add the constant of integration.

Step 1 · Use substitution

To simplify the integral, we will use substitution. Let:

$$ u = 5x - 2. $$

Then, differentiate $u$ with respect to $x$:

$$ \frac{du}{dx} = 5 \quad \Rightarrow \quad dx = \frac{du}{5}. $$

Substitute this into the integral:

$$ I = \int \frac{1}{u^{5/2}}\cdot \frac{du}{5} = \frac{1}{5}\int u^{-5/2}\,du. $$

Step 2 · Integrate

We now integrate $u^{-5/2}$. Using the power rule for integration:

$$ \int u^n\,du = \frac{u^{n+1}}{n+1} + C \quad \text{for } n\neq -1, $$

we get:

$$ \int u^{-5/2}\,du = \frac{u^{-3/2}}{-3/2} = -\frac{2}{3}u^{-3/2}. $$

Step 3 · Substitute back $u = 5x - 2$

Now, substitute back $u = 5x-2$ into the result:

$$ I = \frac{1}{5}\cdot \left(-\frac{2}{3}(5x-2)^{-3/2}\right). $$

Step 4 · Add the constant of integration

Finally, we add the constant of integration $C$ to the result:

$$ I = -\frac{2}{15}(5x-2)^{-3/2} + C. $$


Summary Table

Quantity Value
Substitution$u = 5x-2$
$dx$ in terms of $du$$\tfrac{1}{5}du$
Antiderivative in $u$$-\tfrac{2}{3}u^{-3/2}$

Additional Notes

Result

The solution to the integral is:

$$ I = -\frac{2}{15}(5x-2)^{-3/2} + C. $$