Problem 2
Medium Algebra of Complex Numbers

Find the points corresponding to the complex numbers and…

Find the points corresponding to the complex numbers and determine their position in the complex plane: $$ 1^{\circ}\; i; \quad 2^{\circ}\; -2i; \quad 3^{\circ}\; -1+i; \quad 4^{\circ}\; 2-3i. $$

Explanation of Method

A complex number $z = x + iy$ corresponds to the point $(x, y)$, where $x = \text{Re}(z)$ is plotted on the horizontal (real) axis and $y = \text{Im}(z)$ is plotted on the vertical (imaginary) axis. The plane is split into four quadrants:

  • Quadrant I: $x > 0,\ y > 0$
  • Quadrant II: $x < 0,\ y > 0$
  • Quadrant III: $x < 0,\ y < 0$
  • Quadrant IV: $x > 0,\ y < 0$
  1. Extract the real part $x$ and imaginary part $y$ of $z$.
  2. Plot the point $(x, y)$ and identify which quadrant or axis it falls on.

Step 1° · $z = i$

Writing $z$ in standard form: $z = i = 0 + i \cdot 1$, so $x = 0$, $y = 1$.

$$ \boxed{(0, 1)} $$

This point lies on the positive imaginary axis — on the boundary between Quadrants I and II.

Modulus: $|i| = \sqrt{0^2 + 1^2} = 1$. Argument: $\arg(i) = \dfrac{\pi}{2}$ (90°).

Step 2° · $z = -2i$

Writing $z$ in standard form: $z = -2i = 0 + i \cdot (-2)$, so $x = 0$, $y = -2$.

$$ \boxed{(0, -2)} $$

This point lies on the negative imaginary axis — on the boundary between Quadrants III and IV.

Modulus: $|-2i| = \sqrt{0^2 + (-2)^2} = 2$. Argument: $\arg(-2i) = -\dfrac{\pi}{2}$ (−90° or 270°).

Step 3° · $z = -1 + i$

Writing $z$ in standard form: $z = -1 + i = -1 + i \cdot 1$, so $x = -1$, $y = 1$.

$$ \boxed{(-1, 1)} $$

This point lies in Quadrant II (negative real part, positive imaginary part).

Modulus: $|-1 + i| = \sqrt{(-1)^2 + 1^2} = \sqrt{2}$. Argument: $\arg(-1+i) = \pi - \arctan\!\left(\dfrac{1}{1}\right) = \pi - \dfrac{\pi}{4} = \dfrac{3\pi}{4}$ (135°).

Step 4° · $z = 2 - 3i$

Writing $z$ in standard form: $z = 2 - 3i = 2 + i \cdot (-3)$, so $x = 2$, $y = -3$.

$$ \boxed{(2, -3)} $$

This point lies in Quadrant IV (positive real part, negative imaginary part).

Modulus: $|2 - 3i| = \sqrt{2^2 + (-3)^2} = \sqrt{13}$. Argument: $\arg(2-3i) = -\arctan\!\left(\dfrac{3}{2}\right) \approx -56.31°$ (or $\approx 303.69°$).


Summary Table

Complex number Point $(x, y)$ Position Modulus Argument
$i$$(0, 1)$Positive imaginary axis$1$$\frac{\pi}{2}$
$-2i$$(0, -2)$Negative imaginary axis$2$$-\frac{\pi}{2}$
$-1 + i$$(-1, 1)$Quadrant II$\sqrt{2}$$\frac{3\pi}{4}$
$2 - 3i$$(2, -3)$Quadrant IV$\sqrt{13}$$-\arctan(\frac{3}{2})$

Graphical Representation

Re Im 0 $i$ $-2i$ $-1+i$ $2-3i$

The four points plotted on the complex plane (real axis horizontal, imaginary axis vertical).

Result

Applying $z = x + iy \rightarrow (x, y)$ to each number gives:

$$ \begin{aligned} 1^{\circ}\ i &\rightarrow (0, 1) \quad \text{(positive imaginary axis)} \\ 2^{\circ}\ -2i &\rightarrow (0, -2) \quad \text{(negative imaginary axis)} \\ 3^{\circ}\ -1+i &\rightarrow (-1, 1) \quad \text{(Quadrant II)} \\ 4^{\circ}\ 2-3i &\rightarrow (2, -3) \quad \text{(Quadrant IV)} \end{aligned} $$

Position determination: for $z = x + iy$: Quadrant I if $x>0, y>0$; Quadrant II if $x<0, y>0$; Quadrant III if $x<0, y<0$; Quadrant IV if $x>0, y<0$; on the imaginary axis if $x=0, y\neq 0$; on the real axis if $y=0, x\neq 0$.